AkMaL
Kod · PHP69 qator
function newscom($var)

{

return mysql_result(mysql_query("SELECT COUNT(id) FROM news_comm WHERE user = '$var'"), 0);

}



function status($var)

{

$ChEcKeD = newscom($var);

if ($ChEcKeD == 0 || $ChEcKeD <= 15)

{

$status = '<span style="color:#0000FF;">Yangilardan</span>';

$stars = $ChEcKeD;

}

if ($ChEcKeD >= 16 || $ChEcKeD <= 30)

{

$status = '<span style="color:#0000FF;">aktiv</span>';

$stars = $ChEcKeD;

}

if ($ChEcKeD >= 31 || $ChEcKeD <= 50)

{

$status = '<span style="color:#0000FF;">faol</span>';

$stars = $ChEcKeD;

}

elseif ($ChEcKeD >= 51)

{

$status = '<span style="color:#0000FF;">Sayt faxri</span>';

$stars = $ChEcKeD;

}

else

{

$status = NULL;

$stars = NULL;

}

return $status . (isset($stars) ? '<br/>' : '') . $stars . '<br/>';

}


shuni qayerida xato bor 1-elseif dan o'tolmayapti
40 soniyadan keyin yozdi:
yangilikdagi izohlarga qarab unvon berishi kerak